If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(H)=-16H^2+39H+5.4
We move all terms to the left:
(H)-(-16H^2+39H+5.4)=0
We get rid of parentheses
16H^2-39H+H-5.4=0
We add all the numbers together, and all the variables
16H^2-38H-5.4=0
a = 16; b = -38; c = -5.4;
Δ = b2-4ac
Δ = -382-4·16·(-5.4)
Δ = 1789.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$H_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-\sqrt{1789.6}}{2*16}=\frac{38-\sqrt{1789.6}}{32} $$H_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+\sqrt{1789.6}}{2*16}=\frac{38+\sqrt{1789.6}}{32} $
| 7+7w=-3-3w+9w | | 2(x-8)=9x+47 | | -16-12d=2-11d | | -5x+1+3=6-(4x-3) | | 6x=20+10 | | 14-6v=-7v+8 | | -5w+3(w+5)=17 | | 3(x^2–6x)+21=0 | | 3x−5(x+6)=−2x−14 | | -4u-4u-6=10-6u | | a=700/4 | | 5x-11=16-4x | | 13/2(x-5)=3/2x+15/6 | | -6+13x=10x+6 | | 4(x−3)+3(x+2)=2(4x−5)−(x−4)4x−12+3x+6=8x−10−x+4 | | 7x+5=-35+2x | | 4x+3x−12+6=8x−x−10+4 | | 12-4b+b=-6b+6b | | 2x+4=-1+13 | | -12=-4-7/h | | 5y-3(4y-8)=-11 | | 2.5x+8+3.25x=6.2x-10 | | 6−3w=-2w+5 | | -7+5h=4h+1 | | -2-5x=-6x-4 | | 70-6x=90-46x | | 2(4-3x)+5=(2x-3)=20-5x | | 4(x−3)+3(x+2)=2(4x−5)−(x−4) | | 2/x+4=10 | | 1.5x+2x=17 | | 9u+7=10u | | -3q=-8-29 |